#Space rangers 2 plus

#Space rangers 2 plus

If the curent is 30 m/s, you need 30 meters to turn around, plus 60 meters to accelerate against the current to zero net velocity (30 + 20 + 10 meters). You seem to recall you can turn in any direction in 1 turn. If you have a tail current rather than a head current, you want to reduce thrust to zero before you get there, turn around, and add thrust to slow you down to zero over the target. Your acceleration is much higher, something like 300 m/s for fastest possible ballast drop.Д¬urrent complicates zeroing in a bit, but what you want is generally to be facing into the current once you get there, so you can reduce your net velocity to zero. The same logic applies to dropping ballast, though you can't correct if you drop too much, and your control over deacceleration is kind of chunky. at 100 m/s, you must beging braking at no more than 550 meters. If something is going to distract you, like dropping balast, give yourself a couple of extra turns. That's the distance where you MUST begin braking continously. Take the square of your velocity, after current, divide by your acceleration (10 m/s if I recall), and divide by 2. When you're only worried about one axis, compute the point where you need to start braking. Generally you'll reach near-zero on one axis first, at which point you turn. Once you're pointed the right way, pump your speed up to the maximum. If it's roughly the same X and Y, you want to head northeast. It's been so long that I've forgotten the X/Y conventions, but assuming a normal cartesian layout, if it's a long way Y on not far X, you want to head north. It's an exercise in computing deacceleration on the 3 axes.ДЇirst get your sub pointed in the correct direction. It's essentially a complicated version of Lunar Lander.